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Java™ by example!
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How do I convert a primitive to a String?
There are several ways you can do this. In Java programs, you will often see that a primitive is converted by using the concatenation operator on Strings ("" + primitive). A more performant way is to use the method toString on the Object that represents the primitive or to use the static function valueOf in the String class. Here's an example:
 public class TestProg { public static void main(String args[]) { short p_short = 4; int p_int = 10; long p_long = 2349945821828L; float p_float = 3.1415F; double p_double = 0.00000000004D; boolean p_boolean = false; char p_char = 'E'; char p_array[] = { 'e', 's', 'u', 's' };
System.out.println(""+p_short); // 4 System.out.println(Short.toString(p_short)); // 4 System.out.println(String.valueOf(p_short)); // 4 (casted to an int!) System.out.println(""+p_int); // 10 System.out.println(Integer.toString(p_int)); // 10 System.out.println(String.valueOf(p_int)); // 10 System.out.println(""+p_long); // 2349945821828 System.out.println(Long.toString(p_long)); // 2349945821828 System.out.println(String.valueOf(p_long)); // 2349945821828 System.out.println(""+p_float); // 3.1415 System.out.println(Float.toString(p_float)); // 3.1415 System.out.println(String.valueOf(p_float)); // 3.1415 System.out.println(""+p_double); // 4.0E-11 System.out.println(Double.toString(p_double)); // 4.0E-11 System.out.println(String.valueOf(p_double)); // 4.0E-11 System.out.println(""+p_boolean); // false System.out.println(new Boolean(p_boolean).toString()); // false System.out.println(String.valueOf(p_boolean)); // false System.out.println(""+p_char); // E System.out.println(new Character(p_char).toString()); // E System.out.println(String.valueOf(p_char)); // E System.out.println(""+p_array); // esus System.out.println(p_array.toString()); // [C@1a System.out.println(String.valueOf(p_array)); // esus } }
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(Notice that the Boolean and Character classes do not have a static method toString(). In that case, you have to instantiate an object and call the toString method on it.)
To test out the difference in performance of using toString() or valueOf() over ""+p, I ran the following test:
 public class TestPerformance { public static void main(String args[]) { double p_double = 0.00000000004D; long start, end;
System.out.println("Converting to String using concatenation"); start = System.currentTimeMillis(); for (int i=0; i<100000; i++) String s = "" + p_double; end = System.currentTimeMillis(); System.out.println("\tElapsed time: " + (end - start));
System.out.println("Converting to String using valueOf"); start = System.currentTimeMillis(); for (int i=0; i<100000; i++) String s = String.valueOf(p_double); end = System.currentTimeMillis(); System.out.println("\tElapsed time: " + (end - start));
System.out.println("Converting to String using toString"); start = System.currentTimeMillis(); for (int i=0; i<100000; i++) String s = Double.toString(p_double); end = System.currentTimeMillis(); System.out.println("\tElapsed time: " + (end - start)); } }
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The output (times may vary!) shows a performance gain of almost 20%!
 Converting to String using concatenation Elapsed time: 5270 Converting to String using valueOf Elapsed time: 4230 Converting to String using toString Elapsed time: 4230
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Further Information
Author of answer: unknown
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